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6. De lenzenformule

Gegeven: $\eqalign{ & \frac{1} {f} = \frac{1} {v} + \frac{1} {b}}$

Uitwerking


$
\eqalign{
  & \frac{1}
{f} = \frac{1}
{v} + \frac{1}
{b}  \cr
  & \frac{1}
{f} = \frac{b}
{{vb}} + \frac{v}
{{vb}}  \cr
  & \frac{1}
{f} = \frac{{b + v}}
{{vb}}  \cr
  & f = \frac{{vb}}
{{b + v}} \cr}
$


$
\eqalign{
  & \frac{1}
{f} = \frac{1}
{v} + \frac{1}
{b}  \cr
  & \frac{1}
{v} = \frac{1}
{f} - \frac{1}
{b}  \cr
  & \frac{1}
{v} = \frac{b}
{{bf}} - \frac{f}
{{bf}}  \cr
  & \frac{1}
{v} = \frac{{b - f}}
{{bf}}  \cr
  & v = \frac{{bf}}
{{b - f}} \cr}
$


$
\eqalign{
  & \frac{1}
{f} = \frac{1}
{v} + \frac{1}
{b}  \cr
  & \frac{1}
{b} = \frac{1}
{f} - \frac{1}
{v}  \cr
  & \frac{1}
{b} = \frac{v}
{{fv}} - \frac{f}
{{fv}}  \cr
  & \frac{1}
{b} = \frac{{v - f}}
{{fv}}  \cr
  & b = \frac{{fv}}
{{v - f}} \cr}
$

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