WisFaq!

Hoe integreer je deze functie?

Hoe integreer je $\int{}$ln(x²+1)dx?

Japi
28-10-2004

Antwoord

$\int{}$ln(x²+1).dx =
x.ln(x²+1) - $\int{}$x.d(ln(x²+1)) =
x.ln(x²+1) - $\int{}$x.^2x/_x²+1.dx
x.ln(x²+1) - 2$\int{}$^x2/_x²+1.dx =
x.ln(x²+1) - 2$\int{}$^{(x2+1 - 1)}/_x²+1.dx =
x.ln(x²+1) - 2$\int{}$dx + 2$\int{}$¹/_x²+1.dx = ....

LL
28-10-2004