\require{AMSmath} Aanvulling opgave 5 $ \eqalign{ & y = \sqrt {2x} + 2\sqrt x \cr & y = \sqrt 2 \cdot \sqrt x + 2 \cdot \sqrt x \cr & y = \left( {2 + \sqrt 2 } \right)\sqrt x \cr & y' = \frac{{2 + \sqrt 2 }} {{2\sqrt x }} \cr & y' = \frac{{\sqrt 2 + 1}} {{\sqrt 2 \sqrt x }} \cr & y' = \frac{{\sqrt 2 + 1}} {{\sqrt {2x} }} \cr} $ ©2004-2024 WisFaq
\require{AMSmath}
$ \eqalign{ & y = \sqrt {2x} + 2\sqrt x \cr & y = \sqrt 2 \cdot \sqrt x + 2 \cdot \sqrt x \cr & y = \left( {2 + \sqrt 2 } \right)\sqrt x \cr & y' = \frac{{2 + \sqrt 2 }} {{2\sqrt x }} \cr & y' = \frac{{\sqrt 2 + 1}} {{\sqrt 2 \sqrt x }} \cr & y' = \frac{{\sqrt 2 + 1}} {{\sqrt {2x} }} \cr} $
©2004-2024 WisFaq